in a reaction of 3Cu(s)+ 8HNO3(aq)�¨ 3Cu(NO3)2(aq) +2NO(g) + 4H2O(l). if 5.58 grams of Cu(no3)2 is made how many grams of nitrogen monoxide is present

Answer 1

mols Cu(NO3)2 = grams/molar mass = ?
Use the coefficients in the balanced equation to convert mols Cu(NO3)2 to mols NO.
mols Cu(NO3)2 x (2 mols NO/3 mol Cu(NO3)2) = mols Cu(NO3)2 x 2/3 = ?
The grams NO = mols NO x molar mass NO.