concA=initial+rate*time
concA=.558M+2.2E-2*5 M
= .558M+2.2E-1=.778M
In a reaction A to products, ,4.40 min after the reaction is started concentration of A is 0.588M. The rate of reaction at this point is rate= -change in concentration of A/change in time=2.2x10^-2Mmin^-1. Assume that this rate remains constant for a short period of time.
A. what is concentration of A 5.00min after the reaction?
B. At what time after the reaction is started will concentration of A =0.565M?
please I need help in understanding how to solve this question. I already tried it myself a couple of times but I keep getting the wrong answer.
Thanks.
1 answer