in a reaction 3.0moles of ch4 was react with excess of cl2. 265 g of ccl4 was obtained calculate theoretical yield and percentage of this reaction

Answer 1

The balanced chemical equation for the reaction is:

CH4 + 2Cl2 → CCl4 + 2HCl

Using stoichiometry, we can calculate the theoretical yield of CCl4:

3.0 moles CH4 × (1 mole CCl4/1 mole CH4) × (154 g CCl4/1 mole CCl4) = 694.2 g CCl4

Therefore, the theoretical yield of CCl4 is 694.2 g.

To calculate the percentage yield, we need to divide the actual yield by the theoretical yield and multiply by 100:

Percentage yield = actual yield / theoretical yield × 100

We are given that the actual yield is 265 g. Therefore,

Percentage yield = (265 g / 694.2 g) × 100 = 38.2%

The percentage yield of the reaction is 38.2%.