You must mean 60 milliseconds (ms) rather than 60 m/s, which is a speed.
Signal travel time = 740,000 m / 2*10^8 m/s = 3.7*10^-3 s.
Image processing time = 60*10^-3 s
Call the total 60 + 4 = 64 ms.
Other sources of signal delay can be 112 - 64 = 48 ms.
in a proposed telesurgery application the image will be transmitted at 2*10^8m/s ovwe a roundtrip distance of 740km, the compression and decompression process for the images will take a total of 60m/s. what is the largest permissible value for the sources of delay if total round trip delay is to be at most 112ms.
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