To demonstrate that the multiplication of polynomials is a closed system, let's multiply the two given polynomials, \((x^2 - 1)\) and \((-2x + 5)\).
Step 1: Distribute Each Term
We will use the distributive property (also known as the FOIL method when dealing with binomials) to multiply the polynomials.
\[ (x^2 - 1)(-2x + 5) = x^2 \cdot (-2x) + x^2 \cdot 5 - 1 \cdot (-2x) - 1 \cdot 5 \]
Step 2: Perform the Multiplication
Calculating each term separately:
- \(x^2 \cdot (-2x) = -2x^3\)
- \(x^2 \cdot 5 = 5x^2\)
- \(-1 \cdot (-2x) = 2x\)
- \(-1 \cdot 5 = -5\)
Step 3: Combine Like Terms
Now, let's combine all these results:
\[ -2x^3 + 5x^2 + 2x - 5 \]
Conclusion
The result of the multiplication \((-2x^3 + 5x^2 + 2x - 5)\) is a polynomial because it consists of terms where each term includes a coefficient multiplied by a variable raised to a nonnegative integer exponent (in this case, the exponents are 3, 2, 1, and 0).
Verifying Closed System
Since we started with two polynomials and multiplied them, and the result is still a polynomial, we can conclude that the set of polynomials is closed under multiplication. Thus, multiplying polynomials results in another polynomial, demonstrating that polynomials indeed form a closed system under multiplication.