To determine how many weasels should be black, we first need to understand the genetics of the traits involved.
In a cross involving black (B), white (W), and spotted (BW) weasels, we can set up a Punnett square. Here are the possible gametes from two parents:
- Suppose one parent is homozygous black (BB) and the other parent is homozygous white (WW). The Punnett square would look like this:
B B
-----------
W | BW | BW |
-----------
W | BW | BW |
In this case, all offspring (100%) would be black and white spotted (BW), so if we consider this cross, no offspring would be solid black.
Alternatively, if we consider a cross between two heterozygous parents (BW x BW), the Punnett square would look like this:
B W
-----------
B | BB | BW |
-----------
W | BW | WW |
The results would then be:
- BB (black) = 1
- BW (spotted) = 2
- WW (white) = 1
So the ratio would be 1:2:1 (1 black : 2 spotted : 1 white).
Now, if there are 40 baby weasels from this cross, we apply the 1:2:1 ratio:
- Total parts = 1 (black) + 2 (spotted) + 1 (white) = 4 parts.
- Each part represents \( \frac{40}{4} = 10 \) weasels.
From this ratio, the number of black weasels (BB) would be:
- Black (BB) = 1 part = 10 weasels.
Therefore, from this genetic cross, if 40 baby weasels are born, we can conclude that the number of black weasels would be 10.
Given the options:
A: 00
B: 55
C: 1010
D: 20
None of the options correctly match the derived answer of 10. Please double-check the options provided.