In a poker game, you get 5 cards from a regular deck of 52 cards.
What is the probability that you get full house (i.e. three of a kind and two of another kind) if the first two cards you've got were two aces?
2 answers
The probability of getting a full house with two aces is 0.00144057623049219.
OMG, the bot is right.
But of course it gave no explanation, and both Google and Wikekpedia
give that answer.
3 of a kind = 13*C(4,3) = 52
2 of another kind = 12 * C(4,2) = 72
number of possible "full houses" = 52*72 = 3744
number of combinations of 5 cards = C(52,5) = 2,598,960
prob(full house) = 3744/2,598,960 = appr .0014406
But of course it gave no explanation, and both Google and Wikekpedia
give that answer.
3 of a kind = 13*C(4,3) = 52
2 of another kind = 12 * C(4,2) = 72
number of possible "full houses" = 52*72 = 3744
number of combinations of 5 cards = C(52,5) = 2,598,960
prob(full house) = 3744/2,598,960 = appr .0014406
0 answers