In a playground, there is a model of the old school building that is 6.6 feet long, 3.3 feet wide, and 4.6 feet high. If the real building was 80 feet long and 40 feet wide, how high was it?

4 answers

Cross multiply and solve for x.

6.6/80 = 4.6/x
I did that, and got 368.0, and then made that 3680 and divided that by 66 and got 57.57575757...
80 * 4.6 = 368

368 / 6.6 = 55.7575
so close... I must have messed up somewhere. Thanks!