k=F/x=24/0.08 = 300 N/m
PE = kx²/2 = 300•(0.08)²/2= 0.96 J.
KE=PE
mv²/2 =kx²/2
v=sqrt(kx²/m) = sqrt(300•(0.08)²/0.15) = 3.58 m/s
in a pinball machine, a force of 24 N is used to compress a spring a distance of 0.080m.
a. What is the potential energy stored in the spring?
b. What is the maximum speed tha it van produve in a ball of mass 0.15kg?
1 answer
1 answer