what's the trouble?
The vertex is at (0,0), and tan(π/6) = 1/√3 so the line of the chord is y=x/√3
Now, see where the chord intersects the parabola:
(x/√3)^2 = 4ax
x^2/3 = 4ax
x = 12a
So, the length of the chord is
√((12a)^2 + 64a^2) = 4a√13
In a parabola y²=4ax, the length of the
chord passing through the vertex & inclined to
the x-axis @ an angle π/6 (pi/6) is?
Step plz
1 answer