use the formula a= vf^2-vi^2/2d
vf is the 11,000 and the initial velocity is 0.
the distance is 213
when you put these into the equation you get 284,037.559m/s^2 for acceleration
In a novel from 1866 the author describes a spaceship that is blasted out of a cannon with a speed of about 11.000 m/s. The spaceship is approximately 274 m long but part of it is packed with gunpowder, so it accelerates over a distance of only 213 m. What was the acceleration (in m/s2) experienced by the occupants of the spaceship during the launch?
I set it up using the quadratic physics equation and get .28402755. However, the answer is a few tenths large than that. I was wondering if anyone could help figure out why my answer is way smaller than it should be, but the right numbers.
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