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In a moist room (44m3) 4 kg dry CaCl2 is placed. The room contains 10 g/m3 of H20. How much of the CaCl2 is converted to CaCl2*2H2O?

Temperature 10 deg C. Equilibrium constant is 10^5 atm-2 at 10 deg C.

I've caclulated Kp to 0,0032 atm and then tried to convert to Kc to 1,7089 mol/l. However this can't be right.

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