I don't know what Ero stands for but these are reduction potentials you have written. Multiply equation 2 by 2, reverse it, add to equn 1, and eliminate ions common to both sides (for example you can eliminate some of the OH and some of the H2O) and that will be the net ionic equation.
For b part, reverse equation 2 (and change the sign of Eo), add to equation 1 and that will be the cell potential.
In a methane fuel cell, the chemical energy of the methane is converted into electrical energy instead of heat that would flow during the combustion of methane. Using the half-reactions and reduction potentials given below
a) Write a net equation for the reaction.
b) Calculate the potential for the methane fuel cell.
CO32-(aq) + 7H2O(g) + 8e- -----> CH4(g) + 10OH-(aq) Ero = +0.17 V
O2(g) + 2H2O(g) + 4e- ------> 4OH-(aq) Ero = +0.40 V
2 answers
As you saw in Part B, the vapor above the cyclohexane-acetone solution is composed of both cyclohexane vapor and acetone vapor. What mole fraction of the vapor above the solution, , is cyclohexane
1 answer