In a mass spectrometer, singely ionized carbon-12 (normal carbon of atomic mass number 12) has a radius of curvature of 9 cm. What would be the radius of curvature of singely ionized carbon-14, assuming equal velocities?

Question

In a mass spectrometer, singely ionized carbon-12 (normal carbon of atomic mass number 12) has a radius of curvature of 9 cm.  What would be the radius of curvature of singely ionized carbon-14, assuming equal velocities?

(A) 12.3
(B) 10.5
(C) 7.71
(D) 3.58

bobpursley · Answer

mv^2/r=mv^2/r m12/r12=m14/r14 solve for r14 r14=r12*m14/m12

Arielle · Answer

Don't understand this...can u break it down