P(treat) = 20/36 = ?
P(not) = (36-20)/36 = ?
In a livestock research stations a new drug for a certain fowl disease is being tried. Samples of 36 fowls were diagnosed to have the disease. Twenty (20) fowls were treated with the drug and the rest were not.
(a) Calculate the probability that a fowl picked at random is
(i) Treated with the drug
(ii) Not treated with the drug
1 answer