The Inverting Schmitt Trigger circuit is designed to switch the output voltage between two stable states based on the input voltage. The threshold voltages for switching states are determined by the voltage divider formed by R1 and R2.
In this circuit, the threshold voltages can be calculated using the equation:
Vthreshold = (R2 / (R1 + R2)) * Vsupply
Given that Vsupply is ±12V, R1 = 10kΩ, and R2 = 10kΩ, we can calculate the threshold voltages:
Vthreshold = (10kΩ / (10kΩ + 10kΩ)) * 12V
= (10kΩ / 20kΩ) * 12V
= 0.5 * 12V
= 6V
Therefore, the output voltage will switch when the input voltage crosses the threshold voltages of ±6V.
If VIN = +7V, the input voltage is higher than the positive threshold voltage of +6V. Therefore, the output voltage will be:
Output voltage = -Vsupply
= -(-12V)
= +12V
So the correct answer is:
b) +10V
In a Inverting Schmitt Trigger circuit, the supply voltage is ± 12V. The resistance is R1 = 10kΩ and R2 = 10kΩ. Suppose VIN = +7 V, the output voltage will be:
a) -10v
b) +10v
c) +7v
d) +5v
5 answers
are you sure?
Apologies for the mistake in my previous response. Let's re-evaluate the answer.
In an inverting Schmitt Trigger circuit, the output voltage switches between two stable states based on the input voltage and the thresholds set by the voltage divider formed by R1 and R2.
The threshold voltages for switching states can be calculated as follows:
Vthreshold = (R2 / (R1 + R2)) * Vsupply
Given that Vsupply is ±12V, R1 = 10kΩ, and R2 = 10kΩ, we can calculate the threshold voltages:
Vthreshold = (10kΩ / (10kΩ + 10kΩ)) * 12V
= (10kΩ / 20kΩ) * 12V
= 0.5 * 12V
= 6V
Therefore, the output voltage will switch when the input voltage crosses the threshold voltages of ±6V.
If VIN = +7V, the input voltage is higher than the positive threshold voltage of +6V. Thus, the output voltage will switch to the opposite stable state, which is the negative supply voltage.
Hence, the correct answer is:
a) -10V
In an inverting Schmitt Trigger circuit, the output voltage switches between two stable states based on the input voltage and the thresholds set by the voltage divider formed by R1 and R2.
The threshold voltages for switching states can be calculated as follows:
Vthreshold = (R2 / (R1 + R2)) * Vsupply
Given that Vsupply is ±12V, R1 = 10kΩ, and R2 = 10kΩ, we can calculate the threshold voltages:
Vthreshold = (10kΩ / (10kΩ + 10kΩ)) * 12V
= (10kΩ / 20kΩ) * 12V
= 0.5 * 12V
= 6V
Therefore, the output voltage will switch when the input voltage crosses the threshold voltages of ±6V.
If VIN = +7V, the input voltage is higher than the positive threshold voltage of +6V. Thus, the output voltage will switch to the opposite stable state, which is the negative supply voltage.
Hence, the correct answer is:
a) -10V
what is the real answer? -10v or +10v?
Apologies for the confusion in my previous responses. Let's calculate the correct answer.
In an inverting Schmitt Trigger circuit, when the input voltage is above the positive threshold voltage, the output switches to the negative supply voltage. When the input voltage is below the negative threshold voltage, the output switches to the positive supply voltage.
Given that VIN = +7V and the positive threshold voltage is +6V, the input voltage is higher than the positive threshold voltage. Therefore, the output voltage will switch to the negative supply voltage.
Since the supply voltage is ±12V, the correct answer is:
a) -10V
In an inverting Schmitt Trigger circuit, when the input voltage is above the positive threshold voltage, the output switches to the negative supply voltage. When the input voltage is below the negative threshold voltage, the output switches to the positive supply voltage.
Given that VIN = +7V and the positive threshold voltage is +6V, the input voltage is higher than the positive threshold voltage. Therefore, the output voltage will switch to the negative supply voltage.
Since the supply voltage is ±12V, the correct answer is:
a) -10V
1 answer