In a hydraulic system, the pressure is the same throughout. Therefore, the force applied to the small piston is equal to the force exerted by the large piston. Since the area of the large piston is 100 times that of the small piston, the force exerted by the large piston is 100 times greater than the force applied to the small piston.
So, the force exerted by the large piston is 15 N * 100 = 1500 N.
To find the mass that the large piston can carry, we can use the formula:
Force = mass * gravity
Rearranging the formula, we get:
mass = force / gravity
mass = 1500 N / 9.8 m/s^2
mass ≈ 153.06 kg
Therefore, the large piston can carry approximately 153.06 kg of mass.
In a hydraulic system, the area of the large piston is hundred times of the small piston. If 15 N force is applied to the small piston, how much mass can the large piston carry?
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