In a head on collision,a car stops in 0.18s from a speed of 29 m/s . The driver has a mass of 74 kg, and is, fortunately, tightly strapped into his seat. What force is applied to the driver by his seat belt during that fraction of a second?

Answer 1

F = M*a

M is the Mass and a is the acceleration, which in this case is
29 /0.18 = 161 m/s^2

The answer (F) will be in Newtons.
One Newton is about 0.22 lb force.