In a geometric figure tow intersecting lines creating four angles. If <1 and <3 are a vertical pair, m<1 = ( 4x + 26 ). and m<3 = 98, what is the value of x?

14

72

18

98

1 answer

In the given scenario, we know that angles 1 and 3 are vertical angles. Vertical angles are always equal in measure, so we can set their measures equal to each other:

\[ m\angle 1 = m\angle 3 \]

From the problem, we have:

\[ m\angle 1 = 4x + 26 \] \[ m\angle 3 = 98 \]

Setting these equal gives us the equation:

\[ 4x + 26 = 98 \]

To solve for \(x\), first subtract 26 from both sides:

\[ 4x = 98 - 26 \] \[ 4x = 72 \]

Now, divide both sides by 4:

\[ x = \frac{72}{4} \] \[ x = 18 \]

The value of \(x\) is \(18\). Thus, the answer is:

\[ \boxed{18} \]