E(rolls 12) = 5(1/36)
E(rolls 9,10,11) = 1(9/36)
E(rolls any other ) = 1(26/36)
add them up for your expected win
What do they charge to play the game?
multiply your expected win by 100
In a game of dice, the probability of rolling a 12 is 1/36. The probability of rolling a 9, 10, or 11 is 9/36. The probability of rolling any other number is 26/36. If the player rolls a 12, the player wins $5. If the player rolls a 9, 10, or 11, the player wins $1. Otherwise, the player loses $1. What is the expected value of this game? If the game is played 100 times what are the expected winnings (or losses) of the player? I am at a loss where to start.
1 answer
1 answer