In a dihybrid Punnett Square, when crossing two parents who are heterozygous for both traits, which of the following statements would be correct about the offspring?

Question

Choose TWO correct answers.

The phenotypic ratio would be twelve:four:zero:zero.

Less than half of the offspring would show one of the two recessive phenotypes.

The majority of the offspring would show the dominant phenotype.

The majority of the offspring would be have the same genotype as both parents.

The phenotypic ratio would be nine:three:three:one.

Answer 1

In a dihybrid cross between two parents who are heterozygous for both traits (e.g., AaBb x AaBb), the correct statements about the offspring are:

1. Less than half of the offspring would show one of the two recessive phenotypes. (In this case, less than half refers to the recessive combinations; the phenotypes that show the recessive traits will be much fewer than those showing the dominant traits.)

2. The phenotypic ratio would be nine:three:three:one. (This is the classic phenotypic ratio resulting from a dihybrid cross, where 9 offspring show both dominant traits, 3 show one dominant and one recessive trait, another 3 show the other dominant trait and the recessive trait, and 1 shows both recessive traits.)

The other options provided are not correct in the context of a dihybrid cross.