In a diagram of a landscape plan, the scale is 1 cm = 10
ft. In the diagram, the trees are 3.7 cm apart. How far apart should the actual trees be planted?
(1 point)
O 0.37 ft.
O 37 cm
O 37 ft.
O 370 ft.
3 answers
0.37 ft.
What is the area of triangle APQR to the nearest tenth of a square meter? Drawing is not to
scale.
18 m
25
8 m
(1 point)
O 60.8 m²
O 65.3 m²
O30.4 m²
O 32.7 m²
scale.
18 m
25
8 m
(1 point)
O 60.8 m²
O 65.3 m²
O30.4 m²
O 32.7 m²
We can use the formula for the area of a triangle:
(area) = 1/2 (base)(height)
To find the base and height, we can use the Pythagorean theorem:
(base)^2 + (height)^2 = (hypotenuse)^2
In this case, we can use 18 m as the hypotenuse.
First, we can find the length of segment PQ:
PQ^2 = 18^2 - 8^2 = 256
PQ = 16
Now we can use PQ as the base and find the height:
(height)^2 = 18^2 - 16^2 = 68
height ≈ 8.25
Then we can find the area:
(area) = 1/2 (16)(8.25) ≈ 66.0
Rounding to the nearest tenth, the area of triangle APQR is 66.0 m².
Answer: O 65.3 m²
(area) = 1/2 (base)(height)
To find the base and height, we can use the Pythagorean theorem:
(base)^2 + (height)^2 = (hypotenuse)^2
In this case, we can use 18 m as the hypotenuse.
First, we can find the length of segment PQ:
PQ^2 = 18^2 - 8^2 = 256
PQ = 16
Now we can use PQ as the base and find the height:
(height)^2 = 18^2 - 16^2 = 68
height ≈ 8.25
Then we can find the area:
(area) = 1/2 (16)(8.25) ≈ 66.0
Rounding to the nearest tenth, the area of triangle APQR is 66.0 m².
Answer: O 65.3 m²