There were X t-shirts.
Red = 3x/7.
Blue = x/3.
Yel. = x - (3x/7 + x/3) = x - (9x/21+7x/21) = x - 16x/21 = 5x/21.
R = B + 20.
3x/7 = x/3 + 20.
9x/21 - 7x/21 = 20,
2x/21 = 20,
X = 210 t-shirts.
Yel. = 5x/21 = (5*210)/21 = 50.
in a department store, there were a certain number of red t-shirts, blue t-shirts and yellow t-shirts. 3/7 of the t-shirts were red, 1/3 of them were blue, and the rest were yellow. If there were 20 more red t-shirts than blue t-shirts, how many yellow t-shirts were there?
with no variables like x
1 answer
1 answer