In a deck of 52 cards, 3 cards are chosen. What is the probability that all three card are picture cards? (king, queen, jack)

By the way, we are learning combinations and permutations.

Help would be greatly appreciated!

5 answers

There are four suits in each deck, each with 3 picture cards for a total of 12 picture cards in a deck of 52 (different) cards.

The probability of choosing r objects from a pool of n different objects is
C(n,r) = n! / ((n-r)!r!)
where n!=factorial n = n(n-1)(n-2)...3.2.1
For example,
6!=6*5*4*3*2*1=720

For better learning, you would do well doing some further reading on the subject, such as:
http://www.mathsisfun.com/combinatorics/combinations-permutations.html
is an easy reading.

Please remember, solving a problem without understanding the subject will not help you solve the next ones.
Can you please solve it for me?

Im still a bit confused...
Probability
=C(52,12)
Use your calculator function nCr to calculate C(52,12) where n=52, and r=12.
Or calculate
=52!/((52-12)!(12!))
=52!/(40!*12!)

You need to get familiar with these calculations if you are to learn anything from probabilities.
You have 12/52 for the first choice, 11/51 for the second and 10/50 for the third. Just multiply the three probabilities.

MathMate, your instructions are incorrect for the question asked.

C(52,12) is the number of combinations of 12 different cards that can be made from 52 cards.
Thank you GanonTEK!
Indeed, (12/52)(11/51)(10/50) is the correct answer. My bad!