In a cutting tooth operation on a milling machine, the horizontal force exerted by the milling cutter is 1,5 kN.

The milling cutter has a diameter of 125 mm
and rotates at 70 r/min.
The feed of the milling cutter is 0,175 mm per tooth
and the cutter has 45 teeth.
Calculate the following if the average feed is equal to the tangential cutting force: Power consumed for the feed of milling machine

1 answer

To calculate the power consumed for the feed of a milling machine, we'll first find the relevant parameters mentioned in the problem.

  1. Calculate the Tangential Cutting Force (Fc): The tangential cutting force can be defined as the horizontal force exerted by the milling cutter.

    \[ F_c = 1.5 , \text{kN} = 1500 , \text{N} \]

  2. Find the Cutting Speed (Vc): The formula for the cutting speed \( V_c \) for a circular cutter is given by:

    \[ V_c = \pi \cdot D \cdot N \]

    Where:

    • \( D \) = Diameter of the cutter = 125 mm = 0.125 m
    • \( N \) = Rotational speed in revolutions per minute (rpm) = 70 r/min

    First, convert \( N \) to revolutions per second:

    \[ N = \frac{70}{60} , \text{r/s} \approx 1.1667 , \text{r/s} \]

    Now substitute \( D \) and \( N \):

    \[ V_c = \pi \cdot 0.125 , \text{m} \cdot 1.1667 , \text{r/s} \approx 0.4595 , \text{m/s} \]

  3. Calculate the Power (P): The power consumed by the milling process can be calculated using the formula:

    \[ P = F_c \cdot V_c \]

    Substituting the values we have:

    \[ P = 1500 , \text{N} \cdot 0.4595 , \text{m/s} \approx 689.25 , \text{W} \]

    Converting to kilowatts (1 kW = 1000 W):

    \[ P \approx 0.689 , \text{kW} \]

Thus, the power consumed for the feed of the milling machine is approximately 0.689 kW.