Make a sketch and you should have two similar triangles each of sides 5 and 8.
Assumption: we will assume the ball travels in a straight line, and we will ignore the small actual curvature.
The sum of the two acute angles in each triangle = 90°
So the angle between the two paths of the ball is also 90°
Thus Pythagoras!
Dist^2 = (√89)^2 + (√89)^2 = 178
Dist = √178 = appr 13.34 m
In a cricket, a bowler throws a ball at the height 5m. A ball bounces on the pitch at 8m away. A wicket keeper catches this ball from 5m away at the height of 8m. How much distance the ball has covered after pitch. Please show the method.
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1 answer