since they are of equal weight, their average is just the arithmetic average of the two scores: 87
Why do I suspect that the problem was misstated?
In a course a student's final exam is weighted as heavily as his mid term exam.if a student receives a score of 84 on his final exam 90 on his midterm,what is the average for the course?
5 answers
(84 + 90) / 2 = ?
The final exam is weighed the same as the mid term exam. Therefore, you can add the two numbers and divide by 2.
84 + 90 = 174
174/2 = 87 (answer).
84 + 90 = 174
174/2 = 87 (answer).
In a course a student's final exam is weighted twice as heavily as his mid term exam.if a student receives a score of 84 on his final exam 90 on his midterm,what is the average for the course?
as final exam is weighted twice then
84*2=168
then 168+90=258
the average
258/3=86...is the ans right?
as final exam is weighted twice then
84*2=168
then 168+90=258
the average
258/3=86...is the ans right?
that looks better.