Prob(all wrong) = (4/5)(1/3)(3/5)
= 12/75 = 4/25
prob(at least one) = 1 - 4/25 = 21/25
prob(only one correct)
---> RWW, WRW, WWR
= (1/5)((1/3)(3/5) + (4/5)(2/3)(3/5) + (4/5)(1/3(2/5)
= 3/75 + 24/75 + 8/75
= 35/75
= 7/15
check my arithmetic
in a contest, Bello. Adamu, and Lawi are asked to solve a mathematical problem. the probability that they solve the problem correctly are 1/5, 2/3, and 2/5. find the probability that:(1)None of them solve the problem correctly(2)At least one of them solve the problem correctly(3)Only one of them solves the problem correctly
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