Ba(OH)2 + 2HCl ==> BaCl2 + 2H2O or
2OH^- + 2H^+ ==> 2H2O
You added 0.02145 mol OH^- to 0.0429 mols H^+ to produce 0.02145 mol H2O.
q = mass H2O x specific heat H2O x (Tfinal-Tinitial)
Substitute and solve for q. That gives you q for 0.0215 mols reacted or
q/0.02145 = delta H/mol rxn (but there two mols for this problem) so divide that by 2, then convert to kJ/mol by dividing by 1000. You should get about 57 kJ/mol.
In a constant-pressure calorimeter, 65.0 mL of 0.330 M Ba(OH)2 was added to 65.0 mL of 0.660 M HCl. The reaction caused the temperature of the solution to rise from 23.85 °C to 28.35 °C. If the solution has the same density and specific heat as water, what is ΔH for this reaction (per mole of H2O produced)? answer in kj/mol H20
2 answers
@drBob222,
How did you find the moles of OH and H?
How did you find the moles of OH and H?