q = mass H2O x specific heat H2O x (Tfinal-Tinitial)
You had 0.310 x 0.06 = about 0.0186 mols Ba(OH)2 and that produces 2 mols H2O.
dHrxn = q/0.0186 and divide that by 2 to find per mol H2O.
In a constant-pressure calorimeter, 60.0 mL of 0.310 M Ba(OH)2 was added to 60.0 mL of 0.620 M HCl. The reaction caused the temperature of the solution to rise from 23.44 °C to 27.66 °C. If the solution has the same density and specific heat as water, what is ΔH for this reaction (per mole of H2O produced)? Assume that the total volume is the sum of the individual volumes.
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