In a common test for cardiac function (the "stress test"), the patient walks on an inclined treadmill (Figure 6-46). Estimate the power required from a 70 kg patient when the treadmill is sloping at an angle of 15° and the velocity is 3.10 km/h.

Answer 1

F = m*g = 70kg * 9.8N/kg = 686 N.

V=3.1km/h * 1000m/km * 1h/3600s=0.86 m/s

P = F*V = 686 * 0.86 = 590.7 Joules/s.=
590.7 Watts.

Answer 2

this is very wrong, the question says on an inclined plane hence the force is supposed to be given by mgsin15 degrees

Answer 3

F=mgsin15°
=70×9.8sin 15°
=177.55N

V=3.1km/h (1000m÷1km)×(1h÷3600s)
=0.86m/s

P=FV
=177.55×0.86
=152.69W

Answer 4

P= Fv
F=mgsin° v=3.1*100/3600= 0.86m/s
P=70*9.8*sin°(0.86) W

Answer 5

We are going to calculate force first

F=mgsinÕ
F=(70g)(9.8)sin15°
F=177.55N
now calculate the velocity in m/s
3.1km/h×(1000m/1km)×(1h/3600s

This is dimensions analysis, cancelling km and h we get

0.86m/s

Then we can calculate for power using the formula P=FV where F is the force in N and V is the velocity in m/s.
P=FV=(177.55*0.86)=152.69watts
Thank you