Dealing with NUMBER of coins:
nickels ---- x
dimes ----- 2x
quarters ---- 2x - 4
dealing with VALUE of our coins:
5x + 10(2x) + 25(2x-4) = 575
solve for x and back-substitute
In a collection of nickels, dimes and quarters, there are twice as many dimes as nickels, and 4 fewer quarters than dimes. The total value of the coins is $5.75.
How many nickels are there in the collection ?
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