In a closed system, three objects have the following momentums: 110 kg⋅m/s

Question

, −65 kg⋅m/s
, and −100 kg⋅m/s
. The objects collide and move together. What is the total momentum after the collision?(1 point)
Responses

−55 kg⋅m/s
negative 55 kilograms times meters per second

−275 kg⋅m/s
negative 275 kilograms times meters per second

55 kg⋅m/s
55 kilograms times meters per second

275 kg⋅m/s
275 kilograms times meters per second

Answer 1

To find the total momentum of the system after the collision, we first need to sum the momenta of the three objects.

The momenta are:

1. \( 110 , \text{kg⋅m/s} \)
2. \( -65 , \text{kg⋅m/s} \)
3. \( -100 , \text{kg⋅m/s} \)

Now, we calculate the total momentum:

\[ \text{Total momentum} = 110 + (-65) + (-100) \]

This simplifies to:

\[ = 110 - 65 - 100 \] \[ = 110 - 165 \] \[ = -55 , \text{kg⋅m/s} \]

Therefore, the total momentum after the collision is \(-55 , \text{kg⋅m/s}\).

The correct response is:

−55 kg⋅m/s