Question

In a closed system, three objects have the following momentums: 110 kg⋅m/s
, −65 kg⋅m/s
, and −100 kg⋅m/s
. The objects collide and move together. What is the total momentum after the collision?(1 point)
Responses

−55 kg⋅m/s
negative 55 kilograms times meters per second

−275 kg⋅m/s
negative 275 kilograms times meters per second

55 kg⋅m/s
55 kilograms times meters per second

275 kg⋅m/s

Answer 1

To find the total momentum after the collision, we need to sum the individual momentums of the three objects.

The momentums are:
- \( p_1 = 110 \, \text{kg⋅m/s} \)
- \( p_2 = -65 \, \text{kg⋅m/s} \)
- \( p_3 = -100 \, \text{kg⋅m/s} \)

Now, we can calculate the total momentum \( P_{total} \):

\[
P_{total} = p_1 + p_2 + p_3
\]

\[
P_{total} = 110 + (-65) + (-100)
\]

\[
P_{total} = 110 - 65 - 100
\]

\[
P_{total} = 110 - 165
\]

\[
P_{total} = -55 \, \text{kg⋅m/s}
\]

So, the total momentum after the collision is **−55 kg⋅m/s**.