In a closed system, three objects have the following momentums: 110 kg⋅m/s , −65 kg⋅m/s , and −100 kg⋅m/s . The objects collide and move together. What is the total momentum after the collision?(1 point)

Responses

−55 kg⋅m/s
negative 55 kilograms times meters per second

275 kg⋅m/s
275 kilograms times meters per second

−275 kg⋅m/s
negative 275 kilograms times meters per second

55 kg⋅m/s

1 answer

To find the total momentum after the collision, we first need to sum the momenta of the three objects.

Given momenta:

  • Object 1: \( 110 , \text{kg⋅m/s} \)
  • Object 2: \( -65 , \text{kg⋅m/s} \)
  • Object 3: \( -100 , \text{kg⋅m/s} \)

Now, we can calculate the total momentum:

\[ \text{Total momentum} = 110 , \text{kg⋅m/s} + (-65 , \text{kg⋅m/s}) + (-100 , \text{kg⋅m/s}) \]

Calculating it step-by-step:

  1. Calculate \( 110 - 65 = 45 , \text{kg⋅m/s} \)
  2. Now, calculate \( 45 - 100 = -55 , \text{kg⋅m/s} \)

Thus, the total momentum after the collision is

\[ \text{Total momentum} = -55 , \text{kg⋅m/s} \]

Therefore, the correct response is:

−55 kg⋅m/s (negative 55 kilograms times meters per second).