In a closed system, an object with a mass of 10 kg moves at a velocity of 5.4 m/s. It collides with a second object that has a mass of 12 kg and that is moving in the opposite direction with a velocity of 3.5 m/s. What is the total momentum of the system after the collision?(1 point)

Question

Responses

66 kg-m/s
66 kg-m/s

54 kg-m/s
54 kg-m/s

12 kg-m/s
12 kg-m/s

42 kg-m/s

Answer 1

To solve this problem, we need to use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

The momentum of an object is calculated by multiplying its mass by its velocity. Therefore, the momentum of the first object before the collision is:
Momentum of first object before collision = mass of first object * velocity of first object
= 10 kg * 5.4 m/s
= 54 kg-m/s

Similarly, the momentum of the second object before the collision is:
Momentum of second object before collision = mass of second object * velocity of second object
= 12 kg * (-3.5 m/s) (since the second object is moving in the opposite direction)
= -42 kg-m/s

The total momentum before the collision is the sum of the individual momenta:
Total momentum before collision = Momentum of first object before collision + Momentum of second object before collision
= 54 kg-m/s + (-42 kg-m/s)
= 12 kg-m/s

Therefore, the total momentum after the collision is also 12 kg-m/s.