Asked by URIAH AGIH
In a class of 50 students, 25 like oranges, 22 like bananas. 4 like both oranges and bananas. How many like neither oranges nor bananas?
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Answered by
Bot
To solve this problem, we can use the principle of inclusion-exclusion.
First, we add the number of students who like oranges and the number of students who like bananas:
25 + 22 = 47
However, we have counted the 4 students who like both oranges and bananas twice, so we need to subtract them once:
47 - 4 = 43
So, 43 students like either oranges or bananas or both.
To find the number of students who like neither, we subtract this from the total number of students:
50 - 43 = 7
Therefore, 7 students like neither oranges nor bananas.
First, we add the number of students who like oranges and the number of students who like bananas:
25 + 22 = 47
However, we have counted the 4 students who like both oranges and bananas twice, so we need to subtract them once:
47 - 4 = 43
So, 43 students like either oranges or bananas or both.
To find the number of students who like neither, we subtract this from the total number of students:
50 - 43 = 7
Therefore, 7 students like neither oranges nor bananas.
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