To solve this problem, we can use the concept of probability.
Total number of students = 48
Number of students offering physics = 30
Number of students offering biology = 27
A. Probability of only biology = Number of students offering only biology / Total number of students
Since all students offer at least two subjects,
Number of students offering only biology = Total number of students - Number of students offering both physics and biology = 48 - (30 + 27) = 48 - 57 = 0
Therefore, the probability of only biology = 0/48 = 0
B. Probability of both physics and biology = Number of students offering both physics and biology / Total number of students
Number of students offering both physics and biology = 30 + 27 - Total number of students = 30 + 27 - 48 = 9
Therefore, the probability of both physics and biology = 9/48 = 3/16
C. Probability of physics = Number of students offering physics / Total number of students
Therefore, the probability of physics = 30/48 = 5/8
In a class of 48 student 30 offer physics 27 offer biology.
Each of the student offer at least the two subject
What is the probability at random offered
A. Only biology
B. Both physics and biology
C. Physics
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