In a class of 156 students who took maths and physics they all passed at leat 1 subject 75 pass math and physics.if twice has passed physics find how many students pass math only. Represent in Venn diagram.

Answer 1

In math, please do not paraphrase. Most of the time, every word in the question is important.

I interpret the question as:
In a class of 156 students who all took maths and physics.
They all passed at leat 1 subject. Seventy-five passed both math and physics.if twice this number has passed physics find how many students pass math only. Represent in Venn diagram.
If the above interpretation is correct, then
75 passed both physics and math
150 passed physics. This means that (150-75) passed physics only.
The remainder (156-150) must passed math only, since everyone passed at least one subject.

Please attempt the Venn diagram, and post a link to it if you'd like to have it verified.

Answer 2

Answer

Answer 3

I need answers to this question

Answer 4

75 + 9= 84
156 - 84=72
At least one subject 72+9=81

Answer 5

Your solution seems to be incorrect. Here's the correct solution:

Let the number of students who passed math only be represented by x.

We know that 75 students passed both math and physics.

Twice this number (2*75=150) passed physics.

So, 156 - 150 = 6 students only passed math.

Now, we have to add the students who passed both math and physics (75) to the students who only passed math (6):

75 + 6 = 81 students.

Therefore, 81 students passed math or physics or both.

Here's the Venn diagram for reference: