If the legs are a and b, and the hypotenuse is c, then
a+b=50
ab=282
c^2 = a^2+b^2 = (a+b)^2 - 2ab
= 2500-564
= 1936
so, c = √1936 = 44
1 2 3 6 47 94 141 282
In a certain right triangle, the lengths of the legs have a sum of 50 and a product of 282. What is the length of the hypothenuse?
A. 44
B. 42
C. 40
D. 25squareroot2
1 answer