1/12-0 integral from 0 to 12 for 50+14 sin(pit/12)
1/12 [50 t-14.12/pi cos pit/12] from 0 to 12
50 t28/pi
=58.9
In a certain city the temperature (in degrees Fahrenheit) t hours after 9 a.m. was approximated by the function
T(t) = 50 + 14sin((pi*t)/12).
Find the average temperature (in degrees Fahrenheit) during the period from 9 a.m. to 9 p.m.
I got (1/12)((12/pi)(50(12)-14cos((pi)))+(12/pi)(50(0)-14cos((0)/12))) but it's wrong...
Use wolframalpha website, it helps!
Thank you for your time!
1 answer
1 answer