Given the ratio of zinc to copper is 3 to 16, we can denote the amount of zinc as \( z \) and the amount of copper as \( c \). The ratio can be expressed as:
\[ \frac{z}{c} = \frac{3}{16} \]
From this ratio, we can express the amount of zinc in terms of copper:
\[ z = \frac{3}{16} c \]
You mentioned that the jar contains 656 grams of copper, so we can substitute \( c = 656 \) grams into the equation:
\[ z = \frac{3}{16} \times 656 \]
Now, let's calculate this:
\[ z = \frac{3 \times 656}{16} \]
Calculating the numerator:
\[ 3 \times 656 = 1968 \]
Now, divide by 16:
\[ z = \frac{1968}{16} = 123 \]
Thus, the amount of zinc in the jar is:
\[ \boxed{123} \text{ grams} \]