In a certain chemical process,a lab technician supplies 254 j of heat to a system. At the same time,73 j of work are done on the system by iys surroundings.What is the increase in the internal energy of the system?
2 answers
254-(-73)=327
Since heat is supplied to a system Q=+ve = + 254J = 254J
Since workdone on the system so workdone is negative
Then W= - 73 J
Then change in internal energy ∆U= 254-(-73) = 327 Joule
Since workdone on the system so workdone is negative
Then W= - 73 J
Then change in internal energy ∆U= 254-(-73) = 327 Joule