In a cathode-ray tube, electrons are projected horizontally at 6.4 x 106 m/s and travel a horizontal distance of 4.7 cm across the tube. Find the vertical distance the electrons fall under the influence of gravity during their flight. Give your answer in femtometers.

Answer 1

time to fall= 4.6e-2/6.4e6 sec=7.2e-9 sec
fall distance= .5*9.8*(7.2e-9)^2=2.5e-16m= .25fm