how many moles of butane and oxygen are present?
write the equation
which one will get used up first?
the equation will tell you how many moles of water to expect
convert that to grams
In a butane lighter, 9.2 g of butane combines with 32.9 g of oxygen to form 27.8 g carbon dioxide and how many grams of water?
2 answers
2C4H10 + 13O2 ==> 8CO2 + 10H2O
9.2..............32.9............27.8......?
I can't read the mind of the problem's author but I suspect this is not a limiting reagent problem. If not it can be done another way although what oobleck has shown will ALWAYS work.
I think the problem is getting at the Law of Conservation of Mass, therefore
input grams = output grams
(9.2 + 32.9) = 27.9 + mass H2O. Solve for mass H2O
9.2..............32.9............27.8......?
I can't read the mind of the problem's author but I suspect this is not a limiting reagent problem. If not it can be done another way although what oobleck has shown will ALWAYS work.
I think the problem is getting at the Law of Conservation of Mass, therefore
input grams = output grams
(9.2 + 32.9) = 27.9 + mass H2O. Solve for mass H2O
2 answers