In a box containing 11 red balls, 12 green balls and 5 yellow balls. Two balls are drawn one by one without replacement, what is the probability that
(correct your answers to 4 decimal places.)
both of them are the same color?
both of them are not green?
2 answers
most likely red since there is more red
really? last I checked, 12 > 11
the first ball can be any color. then there are 27 balls left
P(red,red) = 10/27
P(green,green) = 11/27
P(yellow,yellow) = 4/27
So P(same color) = 25/27
the first ball can be any color. then there are 27 balls left
P(red,red) = 10/27
P(green,green) = 11/27
P(yellow,yellow) = 4/27
So P(same color) = 25/27
1 answer