In a bike race, a rider covers a 5 mi flat stretch of road at a speed of s mi/h. She then doubles her speed down a hill 1 mi long. Finally, she reduces her downhill speed bu 12 mi/h as she rides the last 2 mi of the race. What function gives the time t it takes the rider finish the race in terms of s?

Answer 1

time = distance/speed, so

t = 5/s + 1/(2s) + 2/(2s-12) = (13s-66)/(2s^2-12s)