Asked by purna
in a beach side suburb it rains on 20% of days and is windy on 30% of days. if rain and wind are independent, on any particular day find the probability that:
(a) it rains and is windy (b) it does not rain and is not windy (c) it rains or it windy (d) it does not rain or is not windy
(a) it rains and is windy (b) it does not rain and is not windy (c) it rains or it windy (d) it does not rain or is not windy
Answers
Answered by
MathMate
Start with a table:
R=rain (20%), ~R=no rain (80%)
W=windy (30%), ~W=not windy (70%)
If rain and wind are independent, the combined occurrence is the product of the respective probabilities.
Example:
(a)P(R∧W)=.2*.3=0.06
(b)P(~R∧~W=0.8*0.7=0.56
(c)...
Will leave (c) and (d) for you as exercise.
R=rain (20%), ~R=no rain (80%)
W=windy (30%), ~W=not windy (70%)
If rain and wind are independent, the combined occurrence is the product of the respective probabilities.
Example:
(a)P(R∧W)=.2*.3=0.06
(b)P(~R∧~W=0.8*0.7=0.56
(c)...
Will leave (c) and (d) for you as exercise.
Answered by
Steve
(a) .20 * .30 = .06
(b) (1-.20) * .30 = .24
(c) .20 + .30 - .20*.30 = .44
(d) (1-.20) + (1-.30) - (1-.20)(1-.30) = .94
Note that (d) = 1-(a)
(b) (1-.20) * .30 = .24
(c) .20 + .30 - .20*.30 = .44
(d) (1-.20) + (1-.30) - (1-.20)(1-.30) = .94
Note that (d) = 1-(a)
Answered by
Steve
Oops. I misread (b). My answer is ~rain & windy
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