a. V=98mi/h * 1600m/mi * 1h/3600s.=43.6 m/s
V^2 = V0^2 + 2a*d.
a = (V^2-Vo^2)/2d.
a = (1897.1-0)/3.4 = 558 m/s^2.
F = m*a = 15 * 558 = 8370 N.
b. Increased.
In a baseball a pitcher can accelerate a .15kg ball from rest to 98 mi/h in a distance of 1.7m
a) what is the average force exerted on a ball during a pitch?
b)If the mass of the ball is increased, is the force required of the pitcher increased, decreased or unchanged?
2 answers
Work is nice, but be careful with your decimal point. Check answer line.....
0 answers