in a ballistic pendulum experiment, projectile 1 result in a maximum heigh h of the pendulum equal to 2.6 cm. a second projectile causes the pendulum to swing twice as high, h2=5.2 cm. the second projectile was how many times faster than the first?

Answer 1

1/2mv^2=mgh

1/2v^2=gh

v1=√2gh1

v2=√2gh2

v2/v1= (√2gh2)/(√2gh1)=answer

Convert cm to to m and g=9.8m/s^2